Question

Two poles of height 6m and 11m stand on a plane ground .if the distance between their feet is 12 metre .find the distance between their tops​

Answer 1

Answer:

13m

Step-by-step explanation:

11m-6m=5m

AB^2=AC^2+BC^2

        =12^2+5^2

         =144+25

         =169

AB=13m

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Answer 2

Answer:

13 metre

Step-by-step explanation:

Given parameters

The two poles

AB = 11 m and CD = 6m

Distance between both poles (BD) = 12m

Difference lengths of poles = 5m

Then, create a line segment CE parallel to line BD

Draw the line (CE) to the longer pole perpendicularly from the top of the shorter pole and also connect the tops of the poles, clearly forming a right-angled triangle.

From the figure

AE = AB – CD

AE = 11 – 5

AE = 6 m

According to the Pythagoras theorem,

(AC)2 = (AE)2 + (EC)2

(AC)2 = 62 + 122

(AC)2 = 36 + 144

(AC)2 = 169

AC = 13 m

The distance between the tops of two poles is 13 m.