Math, asked by riyasinghri, 1 year ago

Two poles of height 6m and 11m stands vertically on the ground. If the distance between their feet is 12 m find the distance between their tops.

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Answers

Answered by Xosmos
10

Answer:

13 m

Step-by-step explanation: Given: Two poles AD and CE of height 6 m, 11 m respectively. 

Distance between the feet of two poles (DC) = 12 m AD = BC = 6 m BE = CE - BC = 11- 6 = 5 m

To prove : Find AE

Proof : According to Pythagoras theorem,AE2 = AB2 + BE2 AE2 = 122 + 52 = 169 AE = 13. ∴ Distance between the tops of two poles = 13 m.


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Answered by pranitdhanade
0

Answer:

Step-by-step explanation:

Distance between the feet of two poles

(DC) = 12 m

AD = BC = 6 m

BE = CE - BC = 11- 6 = 5 m

To prove : Find AE

According to Pythagoras theorem,

AE2 = AB2 + BE2

AE2 = 122 + 52 = 169

AE = 13.

∴ Distance between the tops of two poles = 13 m.

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