Question

Two poles of height 7 meters and 14 meters stand on a plane. if the distance between their feet is 24 meters, then the distance between their tops is

a.25

b.26

c.27

d.28

Answer 1

Hola !!

Here's your answer..⤵⤵
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Let AB = 14 m

DC = EB = 7 m

BC = DE = 24 m

In ∆AED, angle AED = 90°

AE² + ED² = AD²

7² + 24² = AD²

AD² = 49 + 576

AD² = 625

AD = √625

AD = 25 m

Distance between their tops is 25m.
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Hope it helps

Thanks :)

Answer 2

Hay!!

Dear friend -

The right answer is a. 25

Please check Attachment

According to the question we know that

Dc=7m

We know that the faces facing the rectangle are equal

so,

DC = BE

And DE = BC

Now we need to know AD

we know that ∠ADE = 90°

we used formula Ac² = AB²+BC²

And found our answer

I hope it's help you