Two poles of height 8m and 17m high, stand upright in a playground. if there feet are 12m apart, find the distance between their tops.
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Heya ,
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lovely03:
heya bro
Answered by
53
Hey there !!
➡ Given :-
→ Two poles AB and CD are stand upright on the playground of 8m and 17m respectively.
→ Distance between the feet of two poles (BC) is 12m.
➡ To find:-
→ Distance between the top of the two poles (AC).
➡ Construction :-
→ Draw a line AE CD.
➡ Solution :-)
=> AE = BC = 12m.
And,
=> CE = CD - ED.
=> CE = CD - AB. [ ED = AB]
=> CE = 17 - 8.
=> CE = 9m.
▶ Now,
↪ In ∆AEC,
=> AE CD.
→ ∆AEC is a right angled triangle.
▶ Therefore, By Pythagoras' theorem, we get
=> AC² = AE² + CE².
=> AC² = (12)² + (9)².
=> AC² = 144 + 81.
=> AC² = 225.
=> AC = √225.
✔✔ Hence, the Distance between the top of the two poles is 15m. ✅✅
____________________________________
➡ Given :-
→ Two poles AB and CD are stand upright on the playground of 8m and 17m respectively.
→ Distance between the feet of two poles (BC) is 12m.
➡ To find:-
→ Distance between the top of the two poles (AC).
➡ Construction :-
→ Draw a line AE CD.
➡ Solution :-)
=> AE = BC = 12m.
And,
=> CE = CD - ED.
=> CE = CD - AB. [ ED = AB]
=> CE = 17 - 8.
=> CE = 9m.
▶ Now,
↪ In ∆AEC,
=> AE CD.
→ ∆AEC is a right angled triangle.
▶ Therefore, By Pythagoras' theorem, we get
=> AC² = AE² + CE².
=> AC² = (12)² + (9)².
=> AC² = 144 + 81.
=> AC² = 225.
=> AC = √225.
✔✔ Hence, the Distance between the top of the two poles is 15m. ✅✅
____________________________________
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