two poles of height a meter and b meter are p meter apart. prove that the height of the point of intersect N of the joining the top of each pole to the foot of the opposite pole is ab÷a+b
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height of the point of intersection = ab/(a + b)
Step-by-step explanation:
ΔCOL ≈ ΔCBA
h/a = x/(x + y)
ΔAOL ≈ ΔADC
h/b = y/(x + y)
adding both
h/a + h/b = x/(x + y) +y/(x + y)
=> (bh + ah)/ab = (x + y)/(x + y)
=> h(a + b)/ab = 1
=> h = ab/(a + b)
QED
Similar triangle concept is used
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