Question

Two poles of heights 15m and 7.5m stand upright on the ground the distance between then being 18m . Find the length of a wire stretched form the top of one pole to the top of the other pole

Answer 1

Answer:

40m

Step-by-step explanation:

Length of 1 pole: 15m

Length of 2 pole:7.5m

Distance between the two poles = 18m

Add length of pole 1,pole 2 and the distance between them.

15+7.5+18=22.5+18

=40.5m

Answer 2

The length of a wire stretched form the top of one pole to the top of the other pole is 19.5 m.

Step-by-step explanation:

Consider the provided information.

The length of one pole is 15 m and the length of the another pole is 7.5 m.

The distance between them is 18 m.

Now consider the figure shown below:

BE = CD = 7.5 m

AE = BE + AB

15 = 7.5 + AB

AB = 7.5

BC = 18

Now calculate the value of AC by using Pythagoras theorem:

$AB^2+BC^2=AC^2$

$(7.5)^2+(18)^2=AC^2$

$56.25+324=AC^2$

$AC^2=380.25$

$AC=19.5$

Hence, the length of a wire stretched form the top of one pole to the top of the other pole is 19.5 m.

#Learn more

Solve this question by Pythagoras theorem

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