Question

Two poles of heights 16 m and 7m stand on a plane ground . If the distance between their feet is 12m , the distance between their tops is​

Answer 1

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Two poles of heights 16 m and 7m stand on a plane ground . If the distance between their feet is 12m , the distance between their tops is

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☛Let AB and DE be the two poles.

☛According to the question: AB = 13 m

DE = 7 m

☛Distance between their bottoms = BE = 8 m

☛ Draw a perpendicular DC to AB from D, meeting AB at C.

☛We get: DC = 8m, AC = 6 m

☛Applying, Pythagoras theorem in right-angled triangle ACD, we have,

${AD}^{2} = {DC}^{2} + {AC}^{2}$

${8}^{2} + {6}^{2}$

$64 + 36 = 100$

${AD} = \sqrt{100}$

$AD = 10m$

Answer 2

Answer:

Let AB and DE be the two poles.

☛According to the question: AB = 13 m

DE = 7 m

☛Distance between their bottoms = BE = 8 m

☛ Draw a perpendicular DC to AB from D, meeting AB at C.

☛We get: DC = 8m, AC = 6 m

☛Applying, Pythagoras theorem in right-angled triangle ACD, we have,

AD²=DC²+AC²

8²+6²

64+36=100

AD=10m