Two poles of heights 16m and 7m stand on a plane ground. If the distance between
their feet is 12m, the distance between their tops is
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Let AB and DE be the two poles.
☛According to the question: AB = 13 m
DE = 7 m
☛Distance between their bottoms = BE = 8 m
☛ Draw a perpendicular DC to AB from D, meeting AB at C.
☛We get: DC = 8m, AC = 6 m
☛Applying, Pythagoras theorem in right-angled triangle ACD, we have,
AD²=DC²+AC²
8²+6²
64+36=100
AD=10m
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