Question

two poles of heights 58 m and 10 m stand upright on the ground, the distance between them being 14 m find the lengthof the wire stretched from the top to the pole of one pole to the to of the other pole​

Answer 1

Answer :- Length of string = 50m

Solution Given in attachment

Answer 2

$\large\underline{ \underline{ \sf \maltese \: {Given:-}}}$

• Height of first pole (ED) = 58 m
• Height of second pole (AC) = 10 m
• Distance Between two poles (AD) = 14 m

$\large\underline{ \underline{ \sf \maltese \: {To \: find:-}}}$

• Length of the wire (AE)

$\large\underline{ \underline{ \sf \maltese \: {Solution:-}}}$

Let:–

• AE = length of the wire

$\qquad \blacksquare \: \sf{AB = CD = 14 \: m}$

$\qquad \blacksquare \: \sf{EB = BD - AC = \bigg(58 - 10 \bigg) \: m = 48 \: m}$

~ By using Pythagoras' theorem:–

$\qquad \bull \sf{(AE)^2 = (AB)^2+(EB)^2}$

${:} \implies \sf{(AE)^2=14^2 + 48^2}$

${:} \implies \sf{(AE)^2=2304+196}$

${:} \implies \sf{(AE)^2=2500}$

${:} \implies \sf{AE= \sqrt{2500}}$

${:} \implies \boxed {\frak\red{AE= 50}}$

$\qquad \therefore \: {\underline{\sf{ the \: length \: of \: wire = { 50 \: m}}}}$