Question

Two poles of heights 6 M and 11 M stand on a plane ground. If the distance between the feet of the poles is 12 M. Find the distance between their tops. ​

Answer 1

Given :-

Two poles of heights 6 m and 11 m stand on a plane ground.

Distance between the feet of the poles = 12 m

To Find :-

The distance between their tops.

Solution :-

Let AB and CD be the poles of height 6m and 11m.

Given that,

Two poles of heights 6 m and 11 m stand on a plane ground.

And distance between the feet of the poles is 12 m.

Then, now

CP = 11 – 6 = 5 m

According to the question,

AP = 12 m

By Pythagoras theorem for ΔAPC,

$\sf AP^{2} = PC^{2} + AC^{2}$

Substituting their values,

$\sf (12)^{2} + (5)^{2} = (AC)^{2}$

$\sf AC^{2} = (144+25)$

$\sf AC^{2}=169$

$\sf AC=\sqrt{169}$

$\sf AC=13$

Therefore, the distance between their tops is 13 m.

Answer 2

Answer:

Given: Two poles AB=11 m and CD=6m

Distance between both poles BD=12 m

Then, create a line segment CE parallel to line BD

So, AE=AB−CD=11−5=6 m

In right angled △AEC,

(AC)

2

=(AE)

2

+(AE)

2

=(12)

2

+(5)

2

=144+25=169

⇒AC=13 m

So, the distance between their tops is 13 m.

solution

Step-by-step explanation:

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