Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.
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SOLUTION :
Figure is in the attachment .
Given : Two poles of height 6 m and 11 m.
Distance between the feet of the poles = 12
Let BD & AE be the two poles of height is the 6m and 11m.
BD = CE = 6 m
Again BC = DE = 12
In ∆ ABC, by using Pythagoras theorem,
AB² = AC² + BC²
AB² = 5² + 12²
AB² = 25 + 144
AB² = 169
AB = √169
AB = ±13
AB = 13 m
[Taking positive square root]
Hence, the distance between the tops of the poles = 13 m.
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Attachments:
khushi2:
Where’s the attachment???
Answered by
8
5^2 + 12^2 = distance between the poles ^2
25+144
√169
= 13
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