Question

Two poles of heights 6 m and 11 m stands on plain ground, If the distance between feet of the poles is 12 m. Find the distance between their tops.​

Answer 1

Answer:

18 m

Step-by-step explanation:

because it is vertical from the ground and touch the pole and the both both board distance equal to 12 m + 6 m and write into 18 + 11 - 11 so that is the correct answer 18

Answer 2

Answer:

Therefore, the distance between the top of the two poles is 13 m

Step-by-step explanation:

Let, BD be the distance between the top of the two poles.

       Assume, BD = x meters

As  △BED is a right-angled triangle, right angled at E, therefore 'x' is the hypotenuse.

Now apply the Pythagoras theorem on △BED ,

   $Hypotenuse^{2} = Perpendicular^{2} + Base^{2}$

   $BD^{2} = ED^{2} + BE^{2}\\ \\ x^{2} = 122 + 52 x^{2} = 144 + 25 x^{2} = 169 x = 13 m$