two poles of hieght 6m and 11m stand verti
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Given parameters
The two poles
AB = 11 m and CD = 6m
Distance between both poles (BD) = 12m
Difference lengths of poles = 5m
Then, create a line segment CE parallel to line BD
Draw the line (CE) to the longer pole perpendicularly from the top of the shorter pole and also connect the tops of the poles, clearly forming a right-angled triangle.
From the figure
AE = AB – CD
AE = 11 – 5
AE = 6 m
According to the Pythagoras theorem,
(AC)2 = (AE)2 + (EC)2
(AC)2 = 62 + 122
(AC)2 = 36 + 144
(AC)2 = 169
AC = 13 m
The distance between the tops of two poles is 13 m.
The two poles
AB = 11 m and CD = 6m
Distance between both poles (BD) = 12m
Difference lengths of poles = 5m
Then, create a line segment CE parallel to line BD
Draw the line (CE) to the longer pole perpendicularly from the top of the shorter pole and also connect the tops of the poles, clearly forming a right-angled triangle.
From the figure
AE = AB – CD
AE = 11 – 5
AE = 6 m
According to the Pythagoras theorem,
(AC)2 = (AE)2 + (EC)2
(AC)2 = 62 + 122
(AC)2 = 36 + 144
(AC)2 = 169
AC = 13 m
The distance between the tops of two poles is 13 m.
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