Two poles stand on the ground with their feet 24m apart. If these poles are
respectively 12m and 19m in height, find the distance between their tops
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Answer:- 25 m.
Let AB and CD be the given poles such that
AB = 12 m, CD = 19 m and AC = 24 m.
Join BD.
From B, draw BM ⊥ CD.
Then, CM = AB = 12 m, BM = AC = 24 m.
and MD = CD - CM = (19 - 12) m = 7 m.
Now, ∆BMD is right angled at M.
∴ By Pythagoras’ Theorem :
BD² = BM² + MD² = (24² + 7²) m² = (576 + 49) m²
= 625 m² = (25m²)
→ BD = 25 m.
Hence, the distance between the tops of the poles is 25 m.
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