two positive charger Q1=16C and Q2=4C, separated by a diameter of 3m will produce what force
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ELCTROSTATICS.....
Accordingly to the coloumbs Law .....
F = K Qq / r^2 .........
so here we know that .......
F = 9 × 10^9 × 16 x 4 ÷ 9
so here we get ........
F = 64 × 10^9 .....N m^2/C^2
Thus the force between the charges is 64 x 10^9 N m^2 / C^2.....
______________________________
Hope it helps u...〽⤵
Here is Your Answer
_____________________________
ELCTROSTATICS.....
Accordingly to the coloumbs Law .....
F = K Qq / r^2 .........
so here we know that .......
F = 9 × 10^9 × 16 x 4 ÷ 9
so here we get ........
F = 64 × 10^9 .....N m^2/C^2
Thus the force between the charges is 64 x 10^9 N m^2 / C^2.....
______________________________
Hope it helps u...〽⤵
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