Question

Two positive charges +2 micro coulomb and -16 micro coulomb are separated by a distance of 20 cm. Calculate the force experienced by each

Answer 1

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Answer 2

Answer:

Force, F = 7.2 N

Explanation:

It is given that,

Charge 1, $q_1=+2\ \mu C=+2\times 10^{-6}\ C$

Charge 2, $q_2=-16\ \mu C=-16\times 10^{-6}\ C$

Distance between charges, d = 20 cm = 0.2 m

Force between two charges :

$F=k\dfrac{q_1q_2}{d^2}$

$F=9\times 10^9\times \dfrac{2\times 10^{-6}\times 16\times 10^{-6}}{(0.2)^2}$

F = 7.2 N

The force experienced by each charge is 7.2 N