Two positive charges distant 0.1m apart, repel each other with a force of 18N.If the sum of the charges be 9 micro-coulomb,then calculate their separate values. PLZZ SOLVE THE QUADRATIC PART
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According to Coulomb's law the force between them can be given as
F = K Q1 Q2/ r ^2.
18 = 9 × 10^9 × Q1 × Q2/ 10^-2.
Q1 × Q2 = 2 × 10^ -11.
Q1 + Q2 = 9×10^-6.
Q1= 9×10^-6 - Q2.
THERFORE
(9×10^-6-Q2)× Q2 = 2 × 10^-11.
Let Q2 BE X.
THERFORE
X^2 - 9×10^-6X + 2×10^-11.
X^2 - 9×10^-6X + 20×10^-12.
X^2 -5×10^-6 - 4×10^-6 + 20×10^-12.
X ( X - 5×10^-6 ) -4 ×10^-6 ( X - 5×10^-6).
THEREFORE
X = Q2 = 5 ×10^-6 C = 5 MICRO COULOMB OR X = C = 4 ×10^-6 C = 4 MICRO COULOMB.
Therefore two charges are 4 and 5 micro coloumb.
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