Two positive charges have the sum of the charges to be 9c and repel each other with a force of 18n. If the distance of separation be 0.1m, find the magnitude of the charges.
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Data:Given):1)Q1+Q2=9coloumb.
2)Force=18n
3)Distance between two charges is
0.1 metre.
FORMULA:F=kQ1*Q2÷r^2
SOLUTION:18n=9×10^9×Q1×Q2÷(0.1)^2(k=9×10^9)
Therefore,:18n×0.1×0.1=9×10^9×Q1×Q2
Therefore,Q1×Q2=18n×0.1×0.1×10^-9÷9
Q1×Q2=2n×10^-11.............(I)
Now,Putting the values of Q1...
Given:Q1+Q2=9c
therefore:Q1=9-Q2
Putting the values of Q1 in eq(I)we get,
(9-Q2)×Q2=2n×10^-11
9Q2-Q2^2=2n×10^-11
therefore: Q2^2-9Q2+2n×10^-11(solve quadratic equation!!!!
2)Force=18n
3)Distance between two charges is
0.1 metre.
FORMULA:F=kQ1*Q2÷r^2
SOLUTION:18n=9×10^9×Q1×Q2÷(0.1)^2(k=9×10^9)
Therefore,:18n×0.1×0.1=9×10^9×Q1×Q2
Therefore,Q1×Q2=18n×0.1×0.1×10^-9÷9
Q1×Q2=2n×10^-11.............(I)
Now,Putting the values of Q1...
Given:Q1+Q2=9c
therefore:Q1=9-Q2
Putting the values of Q1 in eq(I)we get,
(9-Q2)×Q2=2n×10^-11
9Q2-Q2^2=2n×10^-11
therefore: Q2^2-9Q2+2n×10^-11(solve quadratic equation!!!!
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