Question

Two positive charges of 20 coulomb are situated at a distance of 60 CM. The neutral point between them is at a distance of 20 CM from the 20 coulomb charge. The charge Q is?

Answer 1

Answer:

Question correction:

two positive charges of 20 coulomb and Q coulomb are........

see the attachment for the answer

Answer 2

Answer:

    The charge Q is 80 coulomb.

Explanation:

          The neutral point between

                                         $\frac{KQ_{1} }{r^{2} } =\frac{KQ_{2} }{r^{2} }$

                                        $\frac{Q_{1} }{r^{2} } =\frac{Q_{2} }{r^{2} }$

                                         $\frac{20}{0.04} =\frac{Q}{0.16}$

                                           $Q=\frac{320}{4}$

                                                $=80 coulomb$.