Question

Two positive charges separated by a distance
2 m each other with a force of 0.36 N. If the combined
charge is 26uC, the charges are​

Answer 1

Explanation:

Let charges be

(A)q

1

+Q

2

=26

q

1

=26−q

2

F=

r

2

KQ

1

q

2

,K=9×10

9

F=0.36

4×0.36=9×10

9

×q

1

q

2

0.16=10

9

×q

1

q

2

0.16×10

−9

=q

1

q

2

⇒0.16×10

−9

=(26−q

2

)q

2

⇒0.16×10

−9

=26q

2

−q

2

2

⇒q

2

2

−26q

2

+0.16×10

−9

Solving quadratic

q

2

≈6

q

1

=26−6=20