Two positive charges separated by a distance 2m each other with a force of 0.36N. If the combined charge is 26 microcoloumbs , the charges are?
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Let the two charges be Q and q
Force of repulsion between these charges is 0.36 N
14πε0×Qq(2m)2=0.36N9×109×Qq4m2=0.36N
Qq=0.36×49×109=16×10-11 C2 ---(1 )
Given that sum of charges is 26×10-6C
Q+q=26×10-6C , Q=26×10-6-q
Putting value of Q in equation (1)
q(26×10-6-q)=16×10-11
q2-26×10-6q+16×10-11=0
q2 -16*10-6-10*10-6 q+16*10-11=0
q(q- 16* 10-6)-10 *10-6(q-16*10-6 )=0
(q-16*10-6)(q-10*10-6)=0
q=16×10-6C or q=10×10-6C
If q=16*10-6C , Q=10*10-6C
If q=10*10-6C , Q=16*10-6C
Value of two charges are 16×10-6C and 10×10-6C
Force of repulsion between these charges is 0.36 N
14πε0×Qq(2m)2=0.36N9×109×Qq4m2=0.36N
Qq=0.36×49×109=16×10-11 C2 ---(1 )
Given that sum of charges is 26×10-6C
Q+q=26×10-6C , Q=26×10-6-q
Putting value of Q in equation (1)
q(26×10-6-q)=16×10-11
q2-26×10-6q+16×10-11=0
q2 -16*10-6-10*10-6 q+16*10-11=0
q(q- 16* 10-6)-10 *10-6(q-16*10-6 )=0
(q-16*10-6)(q-10*10-6)=0
q=16×10-6C or q=10×10-6C
If q=16*10-6C , Q=10*10-6C
If q=10*10-6C , Q=16*10-6C
Value of two charges are 16×10-6C and 10×10-6C
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