Question

two positive integers differ by 4 and sum of their reciprocals is 10/21 . then, one of the number is​

Answer 1

Answer:

Let , one number be X , then the second number is (X + 4).

By condition,

1/x*(1/x+4)=10/21

or,x+x+4/x*(x+4)=10/21

or, 2x+4/x(x+4)=10/21

or,x=3

Hence , one of the number is 3