Math, asked by arpitasona223, 9 months ago

two positive number differ by 2001 . when the larger number is divided by smaller number the quotation is 9 leaving remainder 41 . the sum of the digits of larger number is ?​

Answers

Answered by mhanifa
7

Answer:

14

Step-by-step explanation:

Let numbers be a and b

We get following equations as per given:

  • a-b=2001
  • a=9b+41

Replacing a in first equation to find the value of b:

  • 9b+41-b=2001
  • 8b=1960
  • b=1960/8
  • b=245

Now finding a:

a=2001+b=2246

Finally, finding he sum of digits of the larger number:

2+2+4+6=14

The answer is 14

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