two positive number differ by 2001 . when the larger number is divided by smaller number the quotation is 9 leaving remainder 41 . the sum of the digits of larger number is ?
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Answer:
14
Step-by-step explanation:
Let numbers be a and b
We get following equations as per given:
- a-b=2001
- a=9b+41
Replacing a in first equation to find the value of b:
- 9b+41-b=2001
- 8b=1960
- b=1960/8
- b=245
Now finding a:
a=2001+b=2246
Finally, finding he sum of digits of the larger number:
2+2+4+6=14
The answer is 14
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