Question

Two positive numbers and are such that is greater than . If the difference of these numbers is

5 and their product is 24, find: (i) sum of these numbers (ii) difference of their cubes (iii) sum of their

cubes.​

Answer 1

Answer:

Step-by-step explanation:

x-y=5,xy=24

x=5+y

put in xy=24

(5+y)y=24

5y+y square =24

y square+5y-24=0

by factorisation method

y=3,-8

we will take y=3 ,then x=5+3=8

so sum of these no.'s is 8+3=11,

difference of their cube is 485,

sum of their cube is 539