Question

two positive numbers x and y are such that x is greater than y if the difference of these is 5 and their product is 24 findthe sum of tjese numbers,difference of their cubes and sum of their cubes​

Answer 1

Answer:

1)x=8

2)y=3

Step-by-step explanation:

1)×-y=5

2)xy=24

so,

×-y=5

x=5+y

apply x in 'xy=24'

xy=24

(y+5)×y=24. (x=5+y)

y×y+5y-24=0

y×y+(8-3)y-24=0

y×y+8y-3y-24=0

y(y+8)-3(y+8)=0

(y+8)(y-3)=0

y+8=0. y-3=0

y=-8 it's not possible. y=3

x-y=5

x-3=5

x=8

Answer 2

Answer:

This sum i also want be able to done