Question

two positive point charge of 12 C AND 8C ARE 10CM APART. THE WORK DONE IN BRINGING THEM 4CM CLOSER IS WHAT

Answer 1

Answer:

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Explanation:

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Answer 2

Given: Two positive point charges 12c and 8c are separated by 10cm apart.

To find: The work done in bringing them 4cm closer.

Solution: Work = Final P.E - Initial P.E

$\implies W = \frac{q_1 q_2}{4\pi \epsilon_0 r_2} - \frac{q_1 q_2}{4\pi \epsilon_0 r_1} \\\\\\ \implies W = \frac{q_1 q_2}{4\pi \epsilon_0}\left[\frac{1}{r_2} - \frac{1}{r_1}\right] \\\\\\ \implies W = 12 \times 8 \times 9 \times 10^{9}\left[\frac{1}{4} - \frac{1}{10}\right] \\ \\ \\ \implies W = 12 \times 8 \times 9 \times 10^{9} \times \frac{3}{10} \\ \\ \\ \implies W = \frac{648}{5} \times 10^{9} \\ \\ \\ \implies \boxed{W = 1.296 \times 10^{11}}$

Hence, the work done in bringing them 4cm closer is 1.296 × 10¹¹ J.