two positive point charges 8 microcoulomb and 12 microcoulomb are situated in air 10 cm apart the work done in displacing them 4cm near to each other is?
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Answered by
0
Answer:
34.5
Explanation:
Ui=kqQ/10
Uf=kqQ/2
w=Uf-Ui=34.5
Answered by
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3.456J
F = (9×10^9) (q1q2/r^2)
W = F × d
q1 = 8×10^-6 C
q2 = 12×10^-6 C
r = 10/100 = 0.1m
d = 4/100 = 0.04m
hence W = 3.456J
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