Question

two positive point charges of 0.2 microcoulomb and 0.01 microcoulomb are placed 10 cm apart calculate the amount of work done required by placing the same charges at a distance of 5 cm​

Answer 1

Explanation:

q1 = 0.2 μC

q2 = 0.01 μC

r1 = 10 cm = 0.1 m

r2 = 5 cm = 0.05

Work done in reducing the distance from 10 cm to 5 cm can be calculate by using the relation

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Answer 2

Answer:

q1 = 0.2 μC

q2 = 0.01 μC

r1 = 10 cm = 0.1 m

r2 = 5 cm = 0.05

Work done in reducing the distance from 10 cm to 5 cm can be calculate by using the relation