Question

Two processors a and b have clock frequencies of 700 mhz and 900 mhz respectively. Suppose a can execute an instruction with an average of 3 steps and b can execute with an average of 5 steps. For the execution of the same instruction which processor is faster ?

Answer 1

Answer:

A is faster.

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Answer 2

Answer:

Processor a will be faster in execution.

Explanation:

We can calculate the execution time using basic performance equation.

$t = (n \times s) \div r$

Here,

t = Time required by the processor to execute a program

n = Number of instructions

s = Number of steps required to execute one instruction

r = Clock frequency

Now,

Let n = 1000

Execution time of processor a

$t(a) = (1000 \times 3) \div 700$

That gives us t(a) = 4.28 ( t(a) is execution time of processor a )

Execution time of processor b

$t(b) = (1000 \times 5) \div 900$

That gives us t(b) = 5.55 ( t(b) is execution time of processor b )

Conclusion:

Processing time for processor a is less compared to processor b hence, processor a is faster.