Question

Two projectiles are fired from same point on ground with the same speed at angle of projection 53° and 37° with the horizontal respectively.Which one of the following is true?


Their maximum height will be same


Their horizontal range will be same


Their time of flight will be same


Their horizontal component of velocity will be same

Answer 1

Answer:

Their horizontal range will be same

Explanation:

let for a and b angle of projection are 53° and 37° respectively and their speed is x m/sec

for A

horizontal component of a=3A/5

vertical component of a=4A/5

for B

horizontal component of a=4A/5

vertical component of a=3A/5

range for both

formula for range=horizontal component*vertical component*2/g

for a=3A/5*4A/5*2/5=24A²/125

for b=3A/5*4A/5*2/5=24A²/125

so,

Their horizontal range will be same

Answer 2

Given :  Two projectiles are fired from same point on ground with the same speed at angle of projection 53° and 37° with the horizontal respectively

To find : Which statement is true

Solution:

Horizontal Range =  V² Sin (2α)/g

where α - angle of projection

angle of projection 53°

=> R  = V² Sin (2*53°)/g

=> R  = V² Sin (106°)/g

=> R  = V² Cos(16°)/g   ( as Sin(90° + β ) = Cosβ )

angle of projection 53°

=> R  = V² Sin (2*37°)/g

=> R  = V² Sin (74°)/g  

=> R  = V² Cos(16°)/g   ( as Sin(90° - β ) = Cosβ )

V² Cos(16°)/g =  V² Cos(16°)/g

Hence horizontal range will be same

maximum height will not be same

as initial vertical velocity is different

VSin53°  &  VSin37°  

horizontal component of velocity will not be same

VCos53°  &  VCos37°  

time of flight will not be same

T = 2uSin53°/g  &   2uSin37°/g  

Hence  horizontal range will be same

Learn more:

5.For a particle, thrown from the ground obliquely.ū= (51 +6j)ms "a ...

https://brainly.in/question/11609022

A particle when thrown obliquely from ground, canhave a maximum ...

https://brainly.in/question/11641323