two projectiles are fired with same velocity. if one is projected at an angle 30 ° and the other at 60° to the horizontal then the ratio of their horizontal ranges is?
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Answer:
1:1
Explanation:
HORIZONTAL RANGE OF PROJECTILE(H)=Vo^sin2theta/g
the horizontal range for the one which is projected at 30 degree is
R1=Vo^2sin60degree/g
the horizontal range for the other which is projected as 60degree is
R2=Vo^2sin120degree/g
THE RATIO OF R1/R2 IS
R1/R2=Vo^2sin60degree/Vo^2sin120degree=sin60/sin120=root3 by2/root3 by 2=1:1
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