Question

two projectiles are fired with same velocity. if one is projected at an angle 30 ° and the other at 60° to the horizontal then the ratio of their horizontal ranges is?​

Answer 1

Answer:

1:1

Explanation:

HORIZONTAL RANGE OF PROJECTILE(H)=Vo^sin2theta/g

the horizontal range for the one which is projected at 30 degree is

     R1=Vo^2sin60degree/g

the horizontal range for the other which is projected as 60degree is

   R2=Vo^2sin120degree/g

THE RATIO OF R1/R2 IS

     R1/R2=Vo^2sin60degree/Vo^2sin120degree=sin60/sin120=root3 by2/root3 by 2=1:1