Question

Two projectiles thrown from the same point at angles 600

and 300 with the horizontal attain the same

height. Then find the ratio of their initial velocity​

Answer 1

Answer:

1/√3 will be the answer

Answer 2

Hello mate..

Here Is Your Answer:

GIVEN:

$θ(1) = 60 \\ θ(2) = 30 \\ h(1) = h(2)$

$\pink{formula \: for \: finding \: max \: height \: \frac{ {u}^{2} {sin}^{2} \alpha }{2g} }$

As, H(1) = H(2)

$\huge\frac{ {u}^{2} {sin}^{2} \alpha }{2g} = \frac{ {u}^{2} {sin}^{2} \alpha }{2g}$

2g gets cancelled.

${u(1)}^{2} \ {sin(60)}^{2} = {u(2)}^{2} \ {sin(30)}^{2} \\ \frac{ {u(1)}^{2} }{ {u(2)}^{2} } = \frac{{ \sin }^{2}30}{{ \sin }^{2}60} \\ \frac{1}{ \sqrt{3} } = 1: \sqrt{3}$

HOPE THIS HELPS YOU..