Two protons A and B are placed between two parallel plates having a potential difference V.Will these protons experience equal or unequal force?
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The Boolean expression f (A,B,C)= A[B+C(AB+AC)') can be simplified to
Find the differential equations of y=ae^(x) +be^(2x) +ce^(-3x)
⇒11x2−26x−21=0⇒11x2−33x+7x−21=0⇒11x(x−3)+7(x−3)=0
⇒(11x+7)(x−3)=0⇒x=3,−117
∵ x can not be a negative
⇒x=3
Hence the fraction =2x+1x=73
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