two protons are at a distance of 1*10^-10cm. The forces acting between them are?
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The force F act between the two protons =1/4pi absannol zero x q1q2/r2
given, r=10^-10cm=10^-12m
then,F=9x10^9x(1.6x10^-19)^2/(10^-12)^2
=9x1.6x1.6x10^9x10^-38x10^24
=23.04x10^-5N
given, r=10^-10cm=10^-12m
then,F=9x10^9x(1.6x10^-19)^2/(10^-12)^2
=9x1.6x1.6x10^9x10^-38x10^24
=23.04x10^-5N
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