Question

two protons are placed at a distance of 12 metres equal to 10 power minus 15 M calculate the gravitational force of attraction between them mass of the proton equal to 1.67 into 10 power minus 27 kg is equal to 6.67 into 10 power minus 11 and m square per kg square

Answer 1

Answer:

1.29 x $10^{-66}$ N

Explanation:

By Newton's Law of Gravitation,

F = $\frac{GMm}{r^{2} }$      (Equation 1)

G = 6.67 x $10^{-11}$ N $m^{2}$ $kg^{-2}$

M = m = mass of one proton = 1.67 x $10^{-27}$ kg

r = distance between the centers of the protons = 12 m + diameter of the proton = 12m + (2 x $10^{-15}$ m)

Putting into Equation 1 -

F = 1.29 x $10^{-66}$ N