Question

two protons enter a region of transverse magnetic field. what Will be the ratio of time period of revolution if ratio of Energy is 2root3 is to root 3​

Answer 1

Answer:

time period of revolution when proton enter a region of the transverse magnetic field.

T=2π

qBv

mr

where, q= charge of proton

B= transverse magnetic field

v=speed of proton

r= radius of circular path.

Hence,

Tα

v

1

.. . . .(1)

Kinetic energy,

K=

2

1

mv

2

vα

K

.. . . . . . . .(2)

From equation (1) and (2), we conclude that,

Tα

K

1

K

1

:K

2

=2

2

:

3

(Given)

T

1

:T

2

=

3

:2

2