Question

Two protons of the same charge 1 x 10-19 C are separated by a distance

of 10-15 m. The magnitude of electrostatic force between them will

be ------------​

Answer 1

Answer:

wind force answer is 5 wind force

Answer 2

Given:

The charge on each proton = 1×10^(-19) C

The distance between the two protons = 10^(-15) m

To find:

The magnitude of electrostatic force between the two protons.

Solution:

The formula to find magnitude of electrostatic force is:

F = kq1q2/r²

Here k is a constant whose value is 9×10⁹,

q1 and q2 are the magnitude of charges and r is the distance between them.

On substituting the values:

F = 9×10⁹ × 10^(-19) × 10^(-19) / (10^(-15))²

= 90 N

Hence the magnitude of electrostatic force between them is 90 N.