Question

Two putty balls of equal masses moving in mutually perpendicular directions with equal speed, stick togetner
after collision. If the balls were initially moving with a velocity of 452 m/s each, find the velocity of the
combined mass after collision.

Answer 1

Answer:

$226\sqrt{2}$ m/s

Explanation:

Let the mass of the balls are m

Velocity of the first ball

$\vec v_1=452\hat i$

Velocity of the second ball

$\vec v_2=452\hat j$

From conservation of linear momentum

$m\vec v_1+m\vec v_2=2m\vec v$

$\implies \vec v=\frac{1}{2}(452\hat i+452\hat j)$

$\implies \vec v=226\hat i+226\hat j)$

Therefore the magnitude of velocity

$=|\vec v|$

$=\sqrt{226^2+226^2}$

$=226\sqrt{2}$ m/s

Hope this answer is helpful.

Answer 2

Answer:

=∣

v

∣

=\sqrt{226^2+226^2}=

226

2

+226

2

=226\sqrt{2}=226

2

m/s