Two rabbits started running towards each other, one from a to b and another from b to
a. They cross each other after 1.2 hours and the first rabbit reaches b, 1 hour before the second rabbit reaches
a. If the distance between a and b is 60 km, what is the speed of the slower rabbit?
Answers
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Rabbit A and Rabbit B meet after 1.2 hours later
⇒ Both rabbits have covered a total of 60 km
⇒ They had travelled a total of 1.2 x 2 = 2.4 hours
Find the average speed of both the rabbits:
Total distance = 60 km
Total time = 2.4 hours
Average speed = Total Distance ÷ Total time
Average speed = 60 ÷ 2.4 = 25 km/h
Define x:
Let x be the time needed for Rabbit A to reach Rabbit B
Find the speed of Rabbit A:
Distance = 60 km
Time = x hours
Speed = Distance ÷ Time
Speed = 60/x km/h
Find the speed of Rabbit B:
Rabbit B finished one hour later than Rabbit A
Distance = 60 km
Time = (x + 1) hours
Speed = Distance ÷ Time
Speed = 60/(x + 1) km/h
Solve x:
Rabbit A's speed = 60/x
Rabbit B's speed = 60 /(x + 1)
Average speed = 25 km/h
1/2 ( 60/x + 60/(x + 1) )= 25
60/x + 60/(x + 1) = 50
60(x + 1) + 60x = 50 (x)(x + 1)
60x + 60 + 60x = 50x² + 50x
50x² - 70x - 60 = 0
5x² - 7x - 6 = 0
(x - 2)(5x + 3) = 0
x = 2 or x = -3/5 (rejected, since time cannot be negative)
Find the speed of the slower rabbit:
Speed = 60/(x + 1) km/h
Speed = 60 / (2 + 1)
Speed = 60/3
Speed = 20 km/h
Answer: The slower rabbit is running at 20 km/h
Answer: The speed of the slower Rabit is 20km/hr.✅
Let second rabbit takes x hr with speed s2
First rabbit takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2= 50/x
As they cross each other in 1hr...
Total speed = s1 + s2
Now, T = D / S
Therefore , 50/(s1+s2) = 1
x = 5/2, 1/3
Put x= 5/2 in s2 –> 20km/hr.
Step-by-step explanation: