Math, asked by KING4191, 1 year ago

Two rabbits started running towards each other, one from a to b and another from b to

a. They cross each other after 1.2 hours and the first rabbit reaches b, 1 hour before the second rabbit reaches

a. If the distance between a and b is 60 km, what is the speed of the slower rabbit?

Answers

Answered by TooFree
10

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Rabbit A and Rabbit B meet after 1.2 hours later

⇒ Both rabbits have covered a total of 60 km

⇒ They had travelled a total of 1.2 x 2 = 2.4 hours


Find the average speed of both the rabbits:

Total distance = 60 km

Total time = 2.4 hours

Average speed = Total Distance ÷ Total time

Average speed = 60 ÷ 2.4 = 25 km/h


Define x:

Let x be the time needed for Rabbit A to reach Rabbit B


Find the speed of Rabbit A:

Distance = 60 km

Time = x hours

Speed = Distance ÷ Time

Speed = 60/x km/h


Find the speed of Rabbit B:

Rabbit B finished one hour later than Rabbit A

Distance = 60 km

Time = (x + 1) hours

Speed = Distance ÷ Time

Speed = 60/(x + 1) km/h


Solve x:

Rabbit A's speed = 60/x

Rabbit B's speed = 60 /(x + 1)

Average speed = 25 km/h


1/2 ( 60/x  + 60/(x + 1) )= 25

60/x + 60/(x + 1) = 50

60(x + 1) + 60x = 50 (x)(x + 1)

60x + 60 + 60x = 50x² + 50x

50x² - 70x - 60 = 0

5x² - 7x - 6 = 0

(x - 2)(5x + 3) = 0

x = 2 or x = -3/5 (rejected, since time cannot be negative)


Find the speed of the slower rabbit:

Speed = 60/(x + 1) km/h

Speed = 60 / (2 + 1)

Speed = 60/3

Speed = 20 km/h


Answer: The slower rabbit is running at 20 km/h


Attachments:
Answered by imaman2301
1

Answer: The speed of the slower Rabit is 20km/hr.✅

Let second rabbit takes x hr with speed s2

First rabbit takes x-5/6 hr with speed s1

Total distance = 50km

S1 = 50/(x-(5/6))

S2= 50/x

As they cross each other in 1hr...

Total speed = s1 + s2

Now, T = D / S

Therefore , 50/(s1+s2) = 1

x = 5/2, 1/3

Put x= 5/2 in s2 –> 20km/hr.

Step-by-step explanation:

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