Question

Two race cars, Car X and Car y, are at the starting
of 18. , X Y,
point of a 2-km track at the same time. Car X and 1
Car Y make one lap every 60 s and every 80 s
respectively.
(i) How long, in seconds, will it take for both
of
cars to be back at the starting point at the
same time?
(ii) How long, in minutes, will it take for the
faster car to be 5 laps ahead of the slower car
ADVANCED​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

4 laps of car x = 4×60=240 seconds

3 laps of car y = 3×80 =240 seconds

so after 240 seconds car x and car y will meet at the starting point.

By that time car x will be advanced by one lap.

ii) To be advanced by 5 laps car x will take 240×5 =1200 seconds =20 minutes.