Two race cars Car x and Car y are at the starting points of 2-km track at the same time. Car X and car Y make one lap every 60s and every 80s respectively.
(1)How long in seconds will it take for both cars to be back at the starting point at the same time?
(2) How long in minutes will it take for the faster car to be 5 laps ahead of the slower car?
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Answer:
Both will meet again at start point after LCM(60,80) seconds.
That is 240 seconds.
in time slower car completes one lap,
faster one covers 1 +20/80 lap,
that is 1.25 laps.
After 20 laps faster by slower car car will be 5 laps ahead, time
=20*60
= 1200s
= 20 minutes
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