Question

Two radioactive X_(1) and X_(2) have docay constants 10 lambda and lambda respecttively . If inittially they have the same number of noclei, then the radio of the number of nuclei of X_(1) to that of X_(2)will be 1//e after a time .

Answer 1

The ratio will be t = 1 / 9 λ

Explanation:

Solution:

Nx1(t) / Nx2(t) = 1e  

or N0 e^−10λt

N0 e^−λt = 1 e (Initially, both have same number of nuclei say N0)

or e^−9λt=e^−1

or e = e^9λt

or 9λt = 1 or

t = 1 / 9 λ

Hence the ratio between X1 and X2 is 1 / 9 λ

Answer 2

The time required for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life, T1/2, and the decay