Question

Two rectangles ABCD and EFGH are congruent. If length of rectangle ABCD is 15m and its perimeter is 50 m, then the breadth of EFGH is​

Answer 1

Answer:

10m

the opposites sides of the rectangle are equal

the length=15m

perimeter=50m

let x be the breadth of the rectangle  

therefore, 15+15+x+x=50

                 30+2x=50

                 2x=50-30

                 2x =20

                 x =20/2

                 x=10m

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