Question

two rectangles have same perimeter. the first rectangle has a length of 35 cm and a width of 25 cm. the other rectangle has a breadth of 20 cm. what is the area of this rectangle ? which rectangle has a greater area and by how much.​

Answer 1

Answer:

answer is first rectangle has greater area by 75

Step-by-step explanation:

first find the perimeter of the first rectangle

then find the length of the second rectangle

then find the area of both the rectangles and the compare the area

Answer 2

Given :

• Perimeter of two rectangle are equal
• Length of first rectangle = 35 cm
• Width of first rectangle = 25 cm
• Width of second rectangle = 20cm

Let :

Length of second rectangle = l

To find :

• Area of second rectangle
• Compare area of two rectangle

Formula used :

• Perimeter of rectangle = 2( length + width )
• Area of rectangle = length × width

Solution :

First of all we will find perimeter and area of first rectangle

➝ Perimeter of first rectangle = 2( 35cm + 25cm)

➝ Perimeter of first rectangle = 2( 60cm)

➝ Perimeter of first rectangle = 120 cm

➝ Area of first rectangle = 35 cm × 25cm

➝ Area of first rectangle = 875 cm²

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Now as we know perimeter of both rectangle are equal

➝ Perimeter of second rectangle = Perimeter of first rectangle

➝ 2( l + 20cm ) = 120 cm

➝ ( l + 20cm ) = 120cm/2

➝ l + 20 cm = 60 cm

➝ l = 60cm - 20cm

➝ l = 40cm

➝ Area of second rectangle = 40cm × 20cm

➝ Area of second rectangle = 800cm²

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As we can see area of first rectangle is greater than area of second rectangle.

➝ Difference in area = Area of first rectangle - area of second rectangle

➝ Difference in area = 875 cm² - 800cm²

➝ Difference in area = 75 cm²

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ANSWER :

• Area of second rectangle = 800cm²
• Area of first rectangle is greater than area of second rectangle by 75cm²