two rectangular fields have the same perimeter. one is a square of side 60 m,the other is a rectangle of length 7 dam. which field has the larger area and by how many area (a)?
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Given,
length of rectangle=7m
side of square=60m
1.find the perimeter of square.
P=4Xside
P=4X60
P=240m
2.find the breath
P=2(l+b)
240=2(7+b)
240/2=7+b
120=7+b
120-7=b
113=b
3.area of square. 3.area of rectangle
A=side^2. A=l X b
A=60^2. A=7 X 113
A=3600m^2. A=791m^2
4.compare
3600}791
3600-791=2809m^2
Hence, area of square is greater than area of rectangle by 2809m^2
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