Question

two registers of resistance 2 ohm and 6 Ohm are connected in series 12A a current passes through the circuit find potential difference​

Answer 1

Answer:

96 v

Explanation:

in a series connection R=R1+R2

SO, R= 2ohm+6ohm

R=8 ohm

V=IR

V=8 x 12

v =96volt