Question

Two regular polygon are such that the ratio pf the measures their interior angles is 4 : 3 and the ratio

between their numbers od sides is 2:1. Find the number of sides of each polygon .​

Answer 1

Answer:

ANSWER

Let number of sides of two polygons are n and 2n

measures of interior angles of x sided regular polygon is

x

(x−2)×180°

so

n

n−2

×180°

2n

2n−2

×180°

=

3

4

⇒

2(n−2)

2n−2

=

3

4

⇒6n−6=8n−16

⇒2n=10

⇒n=5

Therefore, number of sides of polygon are 5 and 10.

Step-by-step explanation:

Mark me as brainlieast

Answer 2

Solution(By Examveda Team)

In Give Question,

A + B = 8 ---- (i)

A + C =13 -----(ii)

B + D = 8 ----(iii)

C - D = 6 ----(iv)

Therefore equation (i) and (iii) are equal

A + B = B + D

=> A = D

Therefore, equation (iv) can be C - A = 6 ----- (v)

Now solving equation (ii) and (v), We Get C = 9.5 and A = 3.5

Put this value of A in equation in (i) B = 4.5 and value of C in equation (iv) we get D = 3.5

usually i don't spam but u know what u have spammed my answer so i'm gonna spam ur answer

Did u get that

A = 3.5

B = 4.5

C = 9.5

D = 3.5