Question

Two reservoirs are connected by a pipe line
consisting of two pipes A & B of identical
friction factor and length, and connected in
series. If the diameter of pipe A is 20 percent
larger than tht of B then ratio of the head loss in
A to that in B
(1 marks)​

Answer 1

Answer:

0.5

Step-by-step explanation:

If two pipe in parallel then head loss in both the pipe will be same then 4flv^2/2gd = constant now for the two pipe l, d are same and f1/f2=4 or f2/f1=1/4 then f1v1^2=f2v2^2 then v1/v2= root of f2/f1= root of 1/4 =1/2.

Now Q1/Q2=A1v1/A2v2 =v1/v2 = 1/2 = 0.5.

Answer 2

• If two pipe in parallel then head loss in both the pipe will be same then $4flv^2/2gd$ = constant now for the two pipe l, d are same and $f1/f2=4$ or $f2/f1=1/4$  then $f1v1^2=f2v2^2$ then $f1v1^2=f2v2^2$  

• Now $Q1/Q2=A1v1/A2v2$

                  $=v1/v2$

                  = ?

               

• Now Q1/Q2=A1v1/A2v2 =v1/v2 = 1/2 = 0.5.

             $v1/v2= \sqrt{f2/f1} \\ \\ = \sqrt{1/4} \\ \\ =1/2.$

             $=0.5$