Question

Two reservoirs are connected by a pipe line
consisting of two pipes A & B of identical
friction factor and length and connected in
series. If the diameter of pipe A is 20 percent
larger than tht of B then ratio of the head loss in
A to that in B is
(1 marks)​

Answer 1

Answer:

no idea

Step-by-step explanation:

sorry this question answer ok I don't know

Answer 2

Answer:

$\frac{6}{5}$

Step-by-step explanation:

Head loss $h_{1} =\frac{fLx^{2}}{2gd}$

where,

f= friction factor

L=length of pipe

V= velocity of flow

d=diameter of pipe.

Now,

$h_{A} =\frac{fLx^{2}}{2gd}\\h_{B} =\frac{fLx^{2}}{2gd}$

the diameter of pipe A is 20 percent larger than that of B.

So, the required ratio

$=\frac{h_{A} =\frac{fLx^{2}}{2g6d}}{h_{B} =\frac{fLx^{2}}{2g5d}} \\=\frac{6}{5}$

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