Physics, asked by samkit511, 1 year ago

two resistance 1 ohm and 2 ohm are connected in series and then in parallel the ratio of the effective resistance of the series and parallel combination of resistances

Answers

Answered by ismartshankar77
1

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Answered by komalsharmasharma199
2

Answer:

The ratio of effective resistance of series to parallel.

Explanation:

Concept:

Resistance in series : Resistance in series is written as:

R_{s}=R_{1}+R_{2}

Resistance in parallel: Resistance in parallel is written as:

\frac{1}{R_{p} } =\frac{1}{R_{1} } +\frac{1}{R_{2} }

Given:

R₁=1Ω

R₂=2Ω

Calculations:

Using above formulas we have;

R_{s} = 1+2

    = 3 Ω

\frac{1}{R_{p} }=\frac{1}{1} +\frac{1}{2}\\                      =\frac{2+1}{2} \\                       =\frac{3}{2}

Now, ratio of resistance series to parallel is

\frac{R_{s} }{R_{p} }=\frac{3}{\frac{3}{2} }

\frac{R_{s} }{R_{p} }=\frac{2}{1} }

Result:

The ratio of effective resistance of series to parallel is 2 :1

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